Answer:
sin a = -3/5
Step-by-step explanation:
sin^2(a)+cos^2(a)=1
sin^2(a)+ (4/5)^2 = 1
sin^2(a) = 1 - 16/25 = 9/25
sin a = 3/5 ( in Quadrant 1)
In quadrat IV the sine is negative
so sin a = -3/5
If you are working with time or days, you can't put in a negative value because if you are doing an experiment, you can't go back in time to do that experiment to gather data. (Time for the most part considered to be an input value so that's why I used it as an example.)
Answer:
25 Units/Sq
Step-by-step explanation:
The equation for this line in slope-intercept form is, y=3/5x+3 since 3 is the y-intercept and 3/5 is the slope. If you have any questions about this or anything else let me know! :)
F(-4) = 3 x 2 - 5(-4) + 4
3x2= 6
-5(-4)= 20
6-20= -14
-14+4= -10
f(-4) = -10
