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4 years ago

Can someone please help me

Mathematics

1 answer:

Nat2105 [25]4 years ago

6 0

Answer:

Step-by-step explanation:

abs(x)>0

This statement is false because what happens when x = 0? For all other instances, the statement is true, but not for 0.

Zero is not greater than itself.

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What is the radius for a circle whose equation is x^2+y^2=64

xxTIMURxx [149]

Answer:

8 is the radius.

Step-by-step explanation:

The standard form of a circle is $(x-h)^2+(y-k)^2=r^2$ .

However, I like to call it center-radius form because it tells us the center and the radius.

The center is $(h,k)$ and the radius is $r$ .

So your equation is $(x-0)^2+(y-0)^2=8^2$ .

So the center for this circle is (0,0) and the radius is 8.

If it wasn't so obvious that $8^2$ is 64 then you could have entered $\sqrt{64}$ in your calculator to get 8.

4 0

3 years ago

Find the student’s error in solving the following inequality.

malfutka [58]

Answer:

The correct option is:

The student should have switched the direction of the inequality sign to get –5> x for a final answer

Step-by-step explanation:

The students has made a mistake in the 3rd step.

We know that when we multiply or divide any negative number on both sides of the inequality, the sign of inequality reverse its direction.

In step 3 the student divided 25 by -5 but did not switch direction of the inequality sign.

Therefore the correct option is: The student should have switched the direction of the inequality sign to get –5> x for a final answer....

6 0

3 years ago

Read 2 more answers

Please help I don’t really understand how to go about it.

Airida [17]

$\bf \textit{sum of an arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
S_n=795\\
a_1=102\\
a_n=57
\end{cases}
\\\\\\
795=\cfrac{n(102+57)}{2}\implies 1590=159n
\\\\\\
\cfrac{1590}{159}=n\implies 10=n\\\\
-------------------------------$

so the nth term is really the 10th term, and we know that's 57, thus

$\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=10\\
a_{10}=57\\
a_1=102
\end{cases}
\\\\\\
57=102+(10-1)d\implies 57=102+9d\implies -45=9d
\\\\\\
\cfrac{-45}{9}=d\implies -5=d$

so, that's the common difference... .so you'd surely know what the 3rd term is, notice the first one is 102.

3 0

3 years ago

Please help!!!!! i will mark brainliest

leva [86]

yeah your right

its a

4 0

3 years ago

Read 2 more answers

Alanna is painting a border on a wall. The border consists of kite-shaped figures as shown. mc022-1.jpg Each kite measures 6 inc

Sedaia [141]

the question does not present the picture, but this does not interfere with the resolution

step 1

Find the area of a kite

we know that

area of a kite=(1/2)*[d1*d2]

where d1 and d2 are the diagonals

area of a kite=(1/2)*[6*12]-----> 36 in²

The wall is 12 feet across-----> convert to in-----> 12*12----> 144 in

step 2
find the number of kite to paint
divide across of the wall to across of a kite
144/6-----> 24

step 3
find the number of square inches of the wall to be covered with comets
24*area of one kite-----> 24*36-----> 864 in²

the answer is 864 in²
Note For this calculation, as there is no drawing we have assumed that the diagonal of the 6-inch kite is horizontal

case b)
If the diagonal of the 12-inch kite was horizontal, then the calculation would be
step 2
find the number of kite to paint
divide across of the wall to across of a kite
144/12-----> 12

step 3
find the number of square inches of the wall to be covered with comets
12*area of one kite-----> 12*36-----> 432 in²

the answer would be 432 in²

5 0

4 years ago