De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Answer:
52 adult tickets and 4 children's tickets
Step-by-step explanation:
596=11a+6c
Multiple answers are possible:
Let's use guess and check with (52,4)
596=572+24 when x=54 and y=4
52 adult tickets and 4 children's tickets being sold can total to $596
Answer:
Step-by-step explanation:
Area of the figure = Area of the arc with radius 10 yd and central angle 90° + Area of rectangle with dimensions (10 + 5 - 3 = 12) 12 yd and (7 + 6 - 4 = 9) 9 yd + Area of square with dimension 4yd + Area of rectangle with dimensions 3 yd by 2 yd + Area of triangle with base 3 yd and height (5 + 3 = 8) 8 yd.
Answer:
43.
Step-by-step explanation:
Follow PEMDAS (Parentheses, exponents, multiply, divide, add, subtract). First you do 8-4 which is 4, then you multiply 4 by 4 which is 16 since you multiply next, then you add 27 to 16 which then gets you to 43.
