The cross product of two vectors gives a third vector
that is orthogonal to the first two.
Normalize this vector by dividing it by its norm:
To get another vector orthogonal to the first two, you can just change the sign and use
.
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
Answer:
<M = 32 and <Y = 103
Step-by-step explanation:
1. Since triangle BCM is congruent to triangle ZYR, we know the corresponding parts of the triangles are congruent. Therefore, <Z = <B = 45. The sum of a triangle’s angles is 180, so <M = 180 - <B - <C = 180 - 45 - 103 = 32
2. This is the exact same diagram, so we can use the information we have collected in #1. Since corresponding parts of congruent triangles are congruent, <Y must be congruent to <C, which equals 103. Therefore, <Y = 103.
I hope this helps! :)
Answer: 80
Step-by-step explanation:
