Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of ![1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%20-%200.99%7D%7B2%7D%20%3D%200.905%28%5Btex%5Dt_%7B995%7D)
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Answer:
D. $560
Step-by-step explanation:
800 x .3 equals 240.
800 minus 240 gives you 560
Mark me as brainliest if this helps!
Answer:
Pasos para resolver una ecuación lineal
3x−2/4−2x+5/3=1−x/6
Multiplique ambos lados de la ecuación por 12, el mínimo común denominador de 4,3,6.
36x−3×2−24x+20=12−2x
Multiplica −3 y 2 para obtener −6.
36x−6−24x+20=12−2x
Combina 36x y −24x para obtener 12x.
12x−6+20=12−2x
Suma −6 y 20 para obtener 14.
12x+14=12−2x
Agrega 2x a ambos lados.
12x+14+2x=12
Combina 12x y 2x para obtener 14x.
14x+14=12
Resta 14 en los dos lados.
14x=12−14
Resta 14 de 12 para obtener −2.
14x=−2
Divide los dos lados por 14.
x=
14
−2
Reduzca la fracción
14
−2
a su mínima expresión extrayendo y anulando 2.
x=−
7
1
Step-by-step explanation:
Given table is given below
The relationship between the number of crocodiles and the number of alligators is not proportional across all lakes. Only two of the lakes have crocodiles and alligators in the same proportion. Which two lakes are they?
lake A and lake B
lake B and lake C
lake A and lake E
lake C and lake D
Answer : lake A and lake E
Lake
---> Crocodiles
---> Alligators
---> Ratio
A
---> 4
----> 5
B
---> 21
---> 35
C
---> 3
---> 9
D
---> 6
---> 16
E
---> 24
---> 30
The ratio of A is 4: 5
B is 21: 35 = 3 : 5
C is 3 : 9 = 1 : 3
D is 6 : 16 = 3 : 8
E is 24: 30 = 4 : 5
Lake A and E has the same ratio 4: 5
