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Agata [3.3K]
4 years ago
5

Using the algebraic expression 4n + 6, what is the greatest whole-# value of n that will give you a result less than 100?

Mathematics
1 answer:
Whitepunk [10]4 years ago
6 0
A) 22
4 (22) + 6
88 + 6 = 94

B) 23
4 (23) + 6
92 + 6 = 98

C) 24
4 (24) = 96
96 + 6 = 102

So the answer is B because it is the highest value that can be put into the equation without raising the number to above 100
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What is the inverse of the function g ( x ) = − 3 ( x + 6 ) g(x)=−3(x+6)g, left parenthesis, x, right parenthesis, equals, minus
aleksley [76]

Answer:

Then inverse of the given equation is given by ,f^-1(x)=  (-x/3 - 6)

Step-by-step explanation:

Given:

Function as g(x)=-3(x+6).

To Find :

The inverse function of the g(x).

Solution:

We know that step involving to convert into inverse function as follows :

Further ,

  1. Replace g(x) with function as  "y",

             hence it becomes ,

            y=-3(x+6)

     2.Then solve for the x value ,

        it becomes as ,

      \frac{-y}{3}=x+6,

    \frac{-y}{3}-6=x

     3. Replace x with y and y with x we get ,

   \frac{-x}{3}-6=y.

it is written as ,

y=f^-1(x)=  -x/3-6

Then inverse of the given equation is given by ,f^-1(x)=  -x/3-6.

   

7 0
4 years ago
10+10= hhihihhhiihihihih
svetoff [14.1K]

Answer:

10+10=1010

Step-by-step explanation:

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4 0
3 years ago
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Find the rectangular coordinates of the point. (-5, -180°)
o-na [289]
\bf \begin{array}{rlclll}
(-5&,&-180^o)\\
\uparrow &&\uparrow \\
r&&\theta 
\end{array}\quad 
\begin{cases}
x=rcos(\theta )\\
\qquad -5\cdot cos(-180^o)\\
\qquad -5\cdot -1\\
\qquad 5\\
----------\\
y=rsin(\theta )\\
\qquad -5\cdot sin(-180^o)\\
\qquad -5\cdot 0\\
\qquad 0
\end{cases}\implies (5,0)
4 0
3 years ago
(x+yi)-(-6+14i) = 18+2i <br><br> Can somebody help me solve for X and Y
Viktor [21]
Answer:
Equation A: x = -1 and y = 3
Equation B: x = 12 and y = 16
Step-by-step explanation:
In the complex numbers (a + bi) and (x + yi)
(a + bi) + (x + yi) = (a + x) + (b + y)i
(a + bi) - (x + yi) = (a - x) + (b - y)i
Equation A
∵ (x + yi) + (4 – 7i) = 3 – 4i
∴ (x + 4) + (y - 7)i = 3 - 4i
→ Compare the real parts and compare the imaginary parts
∴ x + 4 = 3 and y - 7 = -4
∵ x + 4 = 3
→ Subtract 4 from both sides
∴ x + 4 - 4 = 3 - 4
∴ x = -1
∵ y - 7 = -4
→ Add 7 to both sides
∴ y - 7 + 7 = -4 + 7
∴ y = 3
Equation B
∵ (x + yi) - (-6 + 14i) = 18 + 2i
∴ (x - -6) + (y - 14)i = 18 + 2i
→ (-)(-) = (+)
∴ (x + 6) + (y - 14)i = 18 + 2i
→ Compare the real parts and compare the imaginary parts
∴ x + 6 = 18 and y - 14 = 2
∵ x + 6 = 18
→ Subtract 6 from both sides
∴ x + 6 - 6 = 18 - 6
∴ x = 12
∵ y - 14 = 2
→ Add 14 to both sides
∴ y - 14 + 14 = 2 + 14
∴ y = 16
5 0
3 years ago
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Asking for a friend please help
Dmitriy789 [7]

Answer:

=1/15

Step-by-step explanation:

4 0
3 years ago
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