Answer:
A. -11
Step-by-step explanation:
In the function, replace x with -2
R(x) = x^2 - 3x - 1 ➡ R(-2) = (-2)^2 - 3 × 2 -1 = -11
Answer:
c i think because the problem =-
Answer:
domain: x>3/5
Step-by-step explanation:
First we need to derive our function g(x) to get a new function g'(x)
To do this we will have to apply chain rule because we have an inner and outer functions.
Our G(x) = square root(3-5x)
Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)
where d/dx(g(f(x)) = g'(x)
g(x) is the outer function which is x^1/2
f(x) is our inner function which is 3-5x
therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5
g'(f(x)) = -1/2(3-5x)^(-1/2)
Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)
But the domain is the values of x where the function g'(x) is not defined
In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined
which gives us x >3/5
Answer:
-3+2sqrt7
-3-2sqrt7
Step-by-step explanation:
x^2+6x-9=10
x^2+6x-9-10=0
x^2+6x-19=0
ax^2+bx+c=0
a=1 b=6 c=-19
As cannot be solved by completing square we will use quadratic equation
x= (-b+sqrt(b^2-4ac))/2a and x= (-b-sqrt(b^2-4ac))/2a
x= (-6+sqrt(6^2-4*-19))/2 and x= (-6-sqrt(6^2-4*-19))/2
x=(-6+sqrt(36+76))/2 and x=(-6-sqrt(36+76))/2
x=(-6+4sqrt7)/2 and x=(-6-4sqrt7)/2
x=(-3+2sqrt7) and x=(-3-2sqrt7)
x=2.29 and x= -8.29
