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2 years ago

I have a volume of 4,680ft3,width of 13ft,and a length of 24ft what is my height

Mathematics

2 answers:

Harrizon [31]2 years ago

8 0

24×13=312

4680/312= 15ft (height)

Schach [20]2 years ago

6 0

15ft is the high and if this is a pool I want it

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Find the value 12 to the second power

Valentin [98]

12 to the second power is equal to 144

(12 x 12)

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3 years ago

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How far do US workers travel to get to their jobs? A researcher would like to collect information on the commute distance travel

Liono4ka [1.6K]

The first answer I have to just guess.

Step-by-step explanation:

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1 year ago

An author published a book which was being sold online. The first month the author sold 21000 books, but the sales were declinin

Wittaler [7]

Answer: 119,616

You may have to erase the comma when inputting the answer.

=======================================================

Explanation:

The author sells 21,000 books in the first month.

Then they sell 21,000*(1-0.12) = 21,000*(0.88) = 18,480 in the second month.

Then they sell 18,480*(1-0.12) = 18,480*(0.88) = 16,262.4 = 16,262 in the third month.

And so on. These values follow a geometric sequence with first term a = 21,000 and common ratio r = 0.88

We can think of the 0.88 as 88% of the original value (since losing 12%, we keep the remaining 88%)

-------------

Use the formula below to sum the first 9 terms of the geometric sequence

Plug in a = 21000 and r = 0.88

$S_n = a*\frac{1-r^n}{1-r}\\\\S_9 = 21000*\frac{1-0.88^9}{1-0.88}\\\\S_9 \approx 21000*\frac{0.6835216}{0.12}\\\\S_9 \approx 21000*5.6960133\\\\S_9 \approx 119,616.2793\\\\S_9 \approx 119,616\\\\$

The author sold about 119,616 books over the course of the first nine months.

4 0

2 years ago

WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$