Question

You pick a card at random. Without putting the first card back, you pick a second card at random.

Answer 1

Probability of first getting a  3 = 4/52 = 1/13
The p(getting >2)  =   probability of getting  one of the remaining 3's or 40 other cards ( Im taking the aces to be low value)  = 43/51

Required probability = 1/13 * 43/51 =  43/663

If aces are counted high it will be 1/13 *  47/51 =   47/531

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