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daser333 [38]
3 years ago
15

Write a real world problem for 5/6 divided by 1/12. Use a model to solve.

Mathematics
1 answer:
sweet [91]3 years ago
6 0
In the year of 2016 1000 high school students graduated from L.D. Bell, 5/6 of the students were A-Honor Roll. 1/12 of those were in NHS. How many of the student were in NHS out of the A-Honor Roll students?
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Suppose that $9500 is placed in an account that pays 8% interest compounded each year.
Blababa [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}


\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}

6 0
3 years ago
Which function has the greatest starting value?. . A.. xy. 1−3. 2−8. 3−13. . . B.. y = 3x – 8. . C.. 8x + 4y = 16. . D.. A linea
nasty-shy [4]
The problem ask to choose among the following functions in the given choices that has the greatest value and the best answer among the following function is letter D. a linear function that goes through point 2,0 and point 0,2. I hope you are satisfied with my answer 
5 0
3 years ago
Meg invests $3,000 in a savings account with 32% simple interest. How
dedylja [7]

Answer:

the answer is $110 i hope this helps but srry if it dont help

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What does 2.45×3.6=? equal
love history [14]
It equals to 8.82 
gl xx
3 0
3 years ago
Identify the zeros of the polynomial function N(x)=1/2 (x-1)(x+3).
zhannawk [14.2K]

Answer:

a:x=-3

c:x=1

Step-by-step explanation:

The zeros of a function are the values of x for which the value of the function f(x) becomes zero.

In this problem, we have the following function:

f(x)=\frac{1}{2}(x-1)(x+3)

Here we want to find the zeros of the function, i.e. the values of x for which

f(x)=0

In order to make f(x) equal to zero, either one of the factors (x-1) or (x+3) must be equal to zero.

Therefore, the two zeros can be found by requiring that:

1)

x-1=0\\\rightarrow x=+1

2)

x+3=0\\\rightarrow x=-3

So the correct options are

a:x=-3

c:x=1

6 0
3 years ago
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