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3 years ago

What is the product of 3/4x1/3x2/5

1 answer:

6 0

The product of 3/4 * 1/3 * 2/5 =

Numerator numbers: 3 * 1 * 2 = 6

Denominator numbers: 4 * 3 * 5 = 60

6/60 is the un-reduced answer.

6/60 --> 1/10

Because 1/10 can go into 6/60.

So the answer is 1/10.

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Someone please help me

umka21 [38]

Answer:

D. 8/5 x

Step-by-step explanation:

7 0

3 years ago

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Consider the equation v + 4 + v = 8. What is the resulting equation after the first step in the solution?

Slav-nsk [51]

Answer:

The resulting equation after the first step is 2v+4=8

d is the correct option

Step-by-step explanation:

We have been given the equation v + 4 + v = 8. In order to solve it for v, we'' perform the below mentioned steps.

Add the like terms in the left hand side
Subtract 4 to both sides of the equation
Finally divide both sides by 2

Hence, in the first step, we can group the like terms and combine. In the left hand side v and v are like terms and hence, we can add them

On adding v and v we get 2v

Thus, we have

$v+v+4=8\\2v+4=8$

Thus, the resulting equation after the first step is 2v+4=8

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3 years ago

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A rectangular picture measuring 5 in. by 9 in. is surrounded by a frame with uniform width x. Write a quadratic function in stan

disa [49]

A=(5+2x)(9+2x)

A=45+10x+18x+4x^2

A=4x^2+28x+45

6 0

3 years ago

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At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl

Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

$n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.$

Let 'p' represents the number of students who take all the three languages, then

$n(A\cap B\cap C)=p.$

Also,

$n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).$

From here, we get after subtracting equation(c) from (b) that

$n(A\cap B)=n(A\cap C)=14.$

Therefore,

$p=14+14-24=4,$ and from equation (a), we find

$n(B\cap C)=24-14=10.$

Thus,

$n(A\cap B\cap C)=4$ and

$n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.$

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

5 0

3 years ago

Need help pls I have the answer but have to show my work

zloy xaker [14]

25.12 but i am not sure i learned this million years ago....
hope i helped

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3 years ago