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Serhud [2]
4 years ago
6

81.5%, 0.815, 33/40 least to greatest

Mathematics
1 answer:
Ainat [17]4 years ago
5 0
81.5% = 0.815
0.815
33/40 = 0.825

u have 2 that are the same
least to greatest :0.815, 0.815, 0.825
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Solve the equation for the given variable. *<br> 3(x - 5) = 7
MariettaO [177]

Answer:

x = 7.33

Step-by-step explanation:

3x - 15 = 7

3x = 7 + 15

3x = 22

x = 7.33

4 0
4 years ago
Can a 3 foot-by-9 foot rectangle be a scaled copy of a 3 foot-by-1 foot rectangle? Explain
Bumek [7]
No,because 9 feet is way bigger than 1 foot.
7 0
4 years ago
Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35​
stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

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4 0
3 years ago
Write $3.9 out of $60 as percentage​
Norma-Jean [14]

Answer:

Step-by-step explanation:

\frac{3.9}{60}*100=\frac{13}{2}

            = 6.5%

4 0
3 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
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Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
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t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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