I need help with 2 questions please thank you.
1 answer:
Hello!
Question 1
In a 30-60-90 triangle the hypotenuse is 2x the height is
and the base is x
Find x
11 = 2x
Divide both sides by 2
5.5 = x
Put in x into the other equations
x = 5.5
2x = 11
11 + 5.5 + 9.5 = 26
We put the equations into a calculator and see which one is close to 26
The answer is B) 33/2 + 11/2 * the square root of 3
------------------------------------------------------------------------------------------------------
Question 2
For this one we can put the choices into a calculator and see what comes up close to 15
tan(86.19°) = 15.01
the answer is D) 86.19°
Hope this helps!
Question 1
In a 30-60-90 triangle the hypotenuse is 2x the height is
Find x
11 = 2x
Divide both sides by 2
5.5 = x
Put in x into the other equations
x = 5.5
2x = 11
11 + 5.5 + 9.5 = 26
We put the equations into a calculator and see which one is close to 26
The answer is B) 33/2 + 11/2 * the square root of 3
------------------------------------------------------------------------------------------------------
Question 2
For this one we can put the choices into a calculator and see what comes up close to 15
tan(86.19°) = 15.01
the answer is D) 86.19°
Hope this helps!
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Answer:
16.1 Inches
Step-by-step explanation:
In ΔKLM,
∠K+∠L+∠M=180°
∠K+161°+18°=180°
∠K+179°=180°
∠K=180°-179°=1°
To determine k in the diagram, we use the Law of Sines.
k X Sin 161°=300 X sin 1°
k=(300 X sin 1°)÷sin 161°
k=16.1 inches (correct to the nearest tenth of an inch)
