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olganol [36]
3 years ago
15

Are all parallelograms squares?

Mathematics
2 answers:
pav-90 [236]3 years ago
6 0
No at least two side need to be parallel to be that so almost anything will be your answer
myrzilka [38]3 years ago
3 0
No, all parallelograms are not squares, but ALL squares are pa<span>rallelograms.</span>
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In Richmond, Chloe ordered $40 worth of sushi. She knew that when the bill came, she would need to pay Richmond sales tax for 5%
maks197457 [2]

Answer:

$50

Step-by-step explanation:

Given data

Cost of sushi= $40

Tax= 5%

Tip= 20%

Let us find the amount of the tax and the tip

Tax

=5/100*40

=0.05*40

=$2

Tip

=20/100*40

=0.2*40

=$8

Hence the total amount paid is

=40+2+8

=$50

6 0
3 years ago
The amount of time it takes to see a doctor a CPT-Memorial is normally distributed with a mean of 33 minutes and a standard devi
Eva8 [605]

Answer:

a) <em>Z-score = 0.75</em>

b) <em>Z-score = -32.833</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that mean of the Population = 33

Given a standard deviation of the Population = 12

Let 'X' be a random variable in a normal distribution

Let 'X' = 42

<u><em>Step(ii):-</em></u>

<em>      </em>Z = \frac{x-mean}{S.D}<em></em>

<em>     </em>Z = \frac{42-33}{12} = 0.75<em></em>

<u><em>Step(iii):-</em></u>

<em>Given that mean of the Population = 89</em>

Given a standard deviation of the Population = 1

Let 'X' be a random variable in a normal distribution

Let 'X⁻ = 82

<em>   </em>Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }<em></em>

<em>     </em>Z = \frac{82-89}{\frac{1}{\sqrt{22} } } =  -32.833<em></em>

<em>Z-score = -32.833</em>

<em></em>

7 0
3 years ago
Is 3/12 equivalent to 1/3
Goshia [24]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write 140 as the product of its prime factors.
Romashka-Z-Leto [24]
140:\bold{2}=70\\\\70:\bold{2}=35\\\\35:\bold{5}=7\\\\7:\bold{7}=\underline{1}

so:

140=2\cdot2\cdot5\cdot7=\boxed{2^2\cdot5\cdot7}
6 0
3 years ago
Read 2 more answers
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
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