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olganol [36]
3 years ago
15

Are all parallelograms squares?

Mathematics
2 answers:
pav-90 [236]3 years ago
6 0
No at least two side need to be parallel to be that so almost anything will be your answer
myrzilka [38]3 years ago
3 0
No, all parallelograms are not squares, but ALL squares are pa<span>rallelograms.</span>
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5 0
3 years ago
The perimeter of the triangle is 15.7 inches, so the equation to solve is 2a + b = 15.7.
zheka24 [161]

Answer:

a=7.85-1/2^b

Step-by-step explanation:

2a=15.7-b Move variable to the right side and change its sign

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a=7.85-1/2^b The final solution for a is


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3 years ago
Will mark as brainlist
lara [203]

Step-by-step explanation:

Tn=ar^(n-1)

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Tn=-5×(2)^(n-1)

Tn=-5•(2)^(n-1)

an=5•(2)^(n-1)

7 0
2 years ago
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VashaNatasha [74]
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6 0
3 years ago
Factorize this expression completely <br>using (a-b)² formula<br>3a²- 36a + 108​
Novosadov [1.4K]

Answer:

3a^2 - 36a + 108  = (\sqrt{3}a - 6\sqrt{3} )^2

Step-by-step explanation:

3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2

so, a = \sqrt{3}  a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}

Therefore ,

3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2  = (\sqrt{3}a - 6\sqrt{3} )^2

6 0
3 years ago
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