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Molodets [167]
3 years ago
13

Which ordered pairs in the form (x, y) are solutions to the equation (x + 7)y = 10? Choose all answers that are correct.  A.(−9,

−5)  B.(−8, 10)  C.(−2, 2)  D.(3, 5)
Mathematics
1 answer:
Elanso [62]3 years ago
8 0
What you do is to substitute the first number for x and the second for y:

(x+7)y=10

a):

(-9+7)*-5=10
(-2)*-5=10
10=10

yes, it's a solution!

b)
(-8+7)10=10
-1*10=10
-10=10

no, not a solution!

c) (-2+7)2=10
5*2=10
yes, a solution!!

d) (3+7)*5=10
50=10

no, not a solution!




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( f – g ) (x) = 8x – 2

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The point (-2,3) is the solution to a system of two linear equations. Which of the following can be one of the
Fynjy0 [20]

Answer:

We conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

Step-by-step explanation:

Given

  • The point (-2, 3)

<u>Checking option A</u>

Given the equation

y = 3x-2

substitute x = -2 and y = 3

3 = 3(-2) - 2

3 = -6 - 2

3 = -8

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y = 3x-2.

<u>Checking option B</u>

Given the equation

y = -x+1

substitute x = -2 and y = 3

3 = -(-2)+1

3 = 2+1

3 = 3

TRUE!

L.H.S = R.H.S

Thus,

The point (-2, 3) satisfies the equation y = -x+1.

<u>Checking option C</u>

Given the equation

y=x-1

substitute x = -2 and y = 3

3 = -2-1

3 = -3

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=x-1.

<u>Checking option D</u>

Given the equation

y=2x+3

substitute x = -2 and y = 3

3 = 2(-2)+3

3 = -4+3

3 = -1

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=2x+3.

Conclusion:

Thus, we conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

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Answer:

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