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3 years ago

10

CAN SOMEONE PLEASE HELP ME WITH THISSSS! Please.

2 answers:

romanna [79]3 years ago

3 0

Answer:

HE broke a rib and he shattered his toe in 5

Step-by-step explanation:

natita [175]3 years ago

3 0

$density = \frac{mass}{volume} \\$

$14.2 = \frac{84.5}{v} \\$

Multiply sides by v

$14.2 \times v = 84.5$

Divided sides by 14.2

$v = \frac{84.5}{14.2} \\$

$v = 5.95 \: \: ml$

_________________________________

And we're done.....♥️♥️♥️♥️♥️

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Reyansh filled a 500-milliliter container with clean water. He then drank 35 percent of the water in the container. How many mil

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answer
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3 years ago

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Kyle’s bank statement shows a balance of –$18.50. Which describes the magnitude, or size, of the debt in dollars?

oksano4ka [1.4K]

Answer:

C. $18.50.

Step-by-step explanation:

We have been given that Kyle’s bank statement shows a balance of –$18.50. We are asked to determine the magnitude, or size, of the debt in dollars.

We know that the magnitude of a negative number is absolute value of negative number.

$\text{Magnitude of debt in dollars}=|-\$18.50|$

Since absolute value of a negative number is opposite of the number.

$\text{Magnitude of debt in dollars}=-(-\$18.50)=\$18.50$

Therefore, option C is the correct choice.

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3 years ago

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poizon [28]

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3 years ago

Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

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