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3 years ago

Please help!!!!!!! I forgot how to do this !!

Mathematics

2 answers:

Doss [256]3 years ago

7 0

Reverse it turn the + into - and the

dem82 [27]3 years ago

7 0

Put the square 2 and make it x2 and 2(2) and you get 4x(2) +4+22=58
Add 22and 4 together and you get 26
Then subtract it by 58 and that's all I got sorry

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I really need help. And its setted up-

Contact [7]

Answer:

4: 300

5: 95

have a good day :]

8 0

3 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago

Please help if you understand!! I hope everyone has a great day or is having a great day

Monica [59]

Answer:

Firstly, notice the relationship the two triangles have. They have conjoining ends that form vertical angles (looks like a middle x). Vertical angles are equivalent in measure of degrees.

Secondly, notice that the triangle on the right side is a right triangle. One of its angle's measurements are also given; 40 degrees. If you know that the sum of a triangle's angles equal 180 degrees, then simply subtract the known angles measurements from 180.

180-(90+40)= 180-130=50.

Therefore, the vertical angles measurement is equivalent to 50 degrees.

Apply the principle of the sum of all angles in a triangle equivalent to 180 degrees to the left triangle, and you will be able to find the measurement of the "?" angle.

180-(50+25)= 180-75=105

SO HERE IS YOUR ANSWER= 105 degrees is the value of the angle marked with a "?"

I hope you are having a great day too;)!

8 0

3 years ago

Read 2 more answers

The first five terms of an arithmetic sequence are shown below: 20, 17, 14, 11, 8, . . . Let n represent the term number and f(n

Leona [35]

Answer: 17 -3n

Explanation:

In the given arithmetic progression 20,17,14,11,8....

first term that is a = 20

common difference that is d= a2-a1 = 17-20 = -3

let n is the nth term

$a_{n}$ = a+(n-1)d

substituting the values of first, common,difference and n

$a_{n}$ =20+(n-1) (-3)

= 20 -3n+3

=23 -3n

6 0

3 years ago

Read 3 more answers

A pilot traveling 175 miles per hour encounters a head wind of 35 knots. If there are 1.15 knots per mph, what will her true spe

KonstantinChe [14]

Since one knot is 1.15 mph.
We multiply 35 time 1.15, which equals 40.25 mph.
Then we subtract. 175 - 4.25 = 134.75
Round, and you'll get 135mph
Therefore, your answer is 135mph

3 0

3 years ago