If the radius of a sphere is increased by a factor of 3, then the volume of the sphere is increased by a factor of

Well, let's imagine that this is a right triangle, rather than an angle.
The verticle side is 800 and the angle of the horizontal side and the hypotenuse is 5 degrees. We can now find what we need. Since we know that one of the angles is 5 degrees and one angle is 90 degrees, we can add 90 + 5 and now we have 95. Now we do 180 - 95 = 85. This is our missing angle. Now we have a full set of angles. Now we can find the missing side lengths. Let's start with the horizontal side. Now we can find the horizontal side length with the sine rule. This gets us 9,144.042. Now we find the hypotenuse using the Pythagorean Theorem. As you may remember, a^2 + b^2 = c^2. For our purposes, we can find it by 9,144.042^2 + 800^2 = c^2. This gets us with 9,178.971. Now we can conclude that the road is <span>9,178.971 feet long, or </span>1.7384414773 miles. I hope this helps you.

5 0

3 years ago

What is this answer?

Elan Coil [88]

The answer will be 12/32

5 0

3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then