Her horizontal distance to the rim satisfies the ratio
(10 ft -6 ft)/distance = tan(25°)
so the distance is
distance = (4 ft)/tan(25°) ≈ 9 ft
Using the change in base property, we have

approximately.
Answer:
.12314
Step-by-step explanation:
Answer:
I Believe you are correct
Step-by-step explanation: