Question

Plss help me do this​

Answer 1

Answer:

x1 = -5

x2 = 3

Step-by-step explanation:

You have the following equation:

$\frac{6}{x}-\frac{4}{5}=\frac{2x}{5}$        (1)

To find the solutions of the equation (1) you first eliminate the denominators of the equation, by multiplying the m.c.m, which is 5x, as follow:

$30-4x=2x^2$

Next, you write the previous equation in the general form ax^2 +bx+c=0, as follow:

$2x^2+4x-30=0$

Next, you use the quadratic formula to find the solutions:

$x_{1,2}=\frac{-b\pm \sqrt{b^2-4(a)(c)}}{2a}\\\\a=2;\ \ b=4;\ \ c=-30\\\\x_{1,2}=\frac{-4\pm \sqrt{4^2-4(2)(-30)}}{2(2)}\\\\x_{1,2}=\frac{-4\pm16}{4}\\\\x_1=-5\\\\x_2=3$

Then, the solutions for the given equation are x1=-5 and x2=3