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bearhunter [10]
4 years ago
7

An exam worth 148 points contains 36 questions. Some questions are worth 2 points, and the others are worth 6 points. How many 2

point and 6 point questions are on the test?
Mathematics
1 answer:
Airida [17]4 years ago
4 0

In order to solve for this question, let's assign a couple variables.

The variable 't' will represent the number of two-point questions, and the variable 's' will represent the number of six point questions.

From the given, we can already form two equations:

t + s = 36

("An exam... contains 36 questions")

2t + 6s = 148

("An exam worth 148 points... Some questions are worth 2 points, and the others are worth 6 points")

Before we begin calculating anything, we can simplify the second equation we made, since all the numbers are divisible by 2:

2t + 6s = 148

t + 3s = 74

Now let's refer back to the first equation. We can subtract both sides by 's' (you could also subtract both sides by 't', but I personally think that this will make solving the equation less difficult):

t + s = 36

t = 36 - s

This effectively gives us a value for the variable 't'. We can assign this value back into our first equation:

t + 3s = 74

(36 - s) + 3s = 74

36 + 2s = 74

2s = 38

s = 19

Input 's' into our second equation to solve for 't':

t = 36 - s

t = 36 - 19

t = 17

There are 17 two-point questions and 19 six-point questions

- T.B.

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mezya [45]

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Step-by-step explanation:

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n200080 [17]

Answer:

Option A. 4, 4.5, 5, 5.5

Step-by-step explanation:

Left point: a=x=4

Right point: b=x=6

Range: r=b-a→r=6-4→r=2

Width of each of the four equal intervals: w=2/4→w=0.5

The first left endpoint is x1=a→x1=4

The second left endpoint is x2=x1+w→x2=4+0.5→x2=4.5

The third left endpoint is x3=x2+w→x3=4.5+0.5→x3=5

The fourth left endpoint is x4=x3+w→x4=5+0.5→x4=5.5

Then, the list is: x1, x2, x3, x4 = 4, 4.5, 5, 5.5

4 0
3 years ago
Evaluate each expression.
Greeley [361]

Answer:

a 16

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Step-by-step explanation:

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