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shtirl [24]
3 years ago
10

√36a3b4 Simplify this.

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0
 the answer is f18ab2<span> • sqrt(oa) </span>
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Which best describe the graph of
Alla [95]
The answer is A) left 3, up 2
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3 years ago
Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.
elena55 [62]

Answer:

x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

Step-by-step explanation:

you have the following formula:

(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1

To solve this equation you use the following properties:

log_aa^x=x

Thne, by using this propwerty in the equation (1) you obtain for x

log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

8 0
3 years ago
The ratio of teachers to students in a school is 1:18.
sineoko [7]

Answer:

if there are 360 students, the number of teacher will be 6,480...

360:6,480

6 0
3 years ago
Read 2 more answers
Please help! if abcd is dilated by a factor of 3, the coordinate of b would be
Nikolay [14]

Answer:

(-6, 6)

Step-by-step explanation:

The coordinates of B to start with is

(-2, 2)

To dilate this by a factor of 3....

-2 * 3 = -6

2 * 3 = 6

The new coordinates of B' would be

(-6, 6)

A few things to know:

- The number 3 is called a "<u>scale factor</u>"

- Dilation means we are multiplying all the (X, Y)'s by the scale factor

- If the scale factor is <u>greater than 1</u>, the size of the shape overall increases

- If the scale factor is <u>less than 1</u>, the size of the shape overall decreases

- If the scale factor is <u>negative</u>, the shape size stays the same. The shape just rotates 180 degrees and moves to the opposite quadrant.

7 0
3 years ago
Read 2 more answers
Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
7 0
3 years ago
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