The rule of law of the square root of constants is taking the nearest divisible number which has a square root of an integer. In this case, 50 is divisible by 25. Hence sqrt of 50 is 5 sqrt 2. The sqrt of a variable applies the multiplication rule. x^6 is raised to 0.5 equal to x^3. Hence the answer is 5 x3 sqrt 2.

3 0

3 years ago

Can y'all help me with number 6.

Juliette [100K]

SOH CAH TOA -> $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}$

so.. which of those fellows do we use?
well, the triangle gives us

the angle, 15 degrees, for elevation angle
the adjacent side, 50m
and we want the opposite side, the slide

so...who has only, the angle, opposite, and adjacent sides?
well, low and behold, is Ms tangent
thus
$\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad 
\begin{cases}
\theta\to 15^o\\
adjacent=50\\
opposite=x-15
\end{cases}
\\ \quad \\
tan(15^o)=\cfrac{x-15}{50}\implies 50tan(15^o)=x-15\\\\ 50\cdot tan(15^o)+15=x$

notice, "x" in the picture, is the distance from the ground up to the top of the waterslide, using that triangle, what we're getting is just the distance, from the shorter slide, to the taller one, or x - 15
thus, the opposite side is x -15

6 0

3 years ago

You must select a team from a group of 6 boys and 10 girls. How many ways can you select 2 boys and 5 girls?

Keith_Richards [23]

Using the combination formula, it is found that you can select 2 boys and 5 girls in 2,520 ways.

In this problem, Joao and Elisa would be the same team as Elisa and Joao, hence the order is not important and the <em>combination formula</em> is used to solve this question.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem:

2 boys are selected from a set of 6.

5 girls are selected from a set of 10.

Hence:

$T = C_{5,2}C_{10,5} = \frac{5!}{3!2!} \times \frac{10!}{5!5!} = 2520$

You can select 2 boys and 5 girls in 2,520 ways.

More can be learned about the combination formula at brainly.com/question/25821700

#SPJ1

6 0

2 years ago

Please Help ASAP ThankYou<br><br>What is the midpoint of EC?

nalin [4]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ E(\stackrel{x_1}{2t}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{2p}~,~\stackrel{y_2}{2r}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{2p+2t}{2}~~,~~\cfrac{2r+0}{2} \right)\implies \left( \cfrac{2(p+t)}{2}~,~\cfrac{2r}{2} \right)\implies (p+t~~,~~r)$

3 0

3 years ago