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lapo4ka [179]
3 years ago
14

Hi Can you check number 5 please If wrong give me right answer

Mathematics
1 answer:
Anna [14]3 years ago
7 0
2 2/4 it is 2 and 2 4
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store a sells a 100 oz bottle of cleaner for $12.99 store B sells the same cleaner for $9.49 for a 70 ounce bottle and store sel
solmaris [256]

Answer:

Store C

Step-by-step explanation:

Simply divide the price by the amount to determine which store has the best price efficiency.

A : 12.99 / 100 = .129¢ per oz

B : 9.49 / 70 = .136¢ per oz

C: 10.98 / 90 = .122¢ per oz

Store C has the best price efficiency

3 0
3 years ago
X2 + 9x+ c <br><br><br> A. 81/4<br> B. 81/2<br> C. 9/4<br> D. 9/2
VikaD [51]

Answer:

hope it would help you

Step-by-step explanation:

the ans should be A

mark my ans as BRAIN LIST

8 0
2 years ago
Read 2 more answers
1
Annette [7]

Answer:

x = 12√1.5

Step-by-step explanation:

Law of sines.

12/sin45 = x/sin60

x = 12(½√3) / (½√2)

x = 12√3/√2

x = 12√1.5

7 0
2 years ago
A random sample of 5120 permanent dwellings on an entire reservation showed that 1627 were traditional hogans.
krek1111 [17]

Answer:

a) \hat p=\frac{1627}{5120}=0.3178

b)The 99% confidence interval would be given by (0.301;0.355)

Step-by-step explanation:

1) Notation and definitions

X=1627 number of permanent dwellings on the entire reservation that are traditional hogans.

n=5120 random sample taken

\hat p=\frac{1627}{5120}=0.318 estimated proportion of permanent dwellings on the entire reservation that are traditional hogans.

p true population proportion of permanent dwellings on the entire reservation that are traditional hogans.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Part a

The point of estimate for p=the proportion of all permanent dwellings on the entire reservation that are traditional hogans is given by:

\hat p=\frac{1627}{5120}=0.3178

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.318 - 2.58\sqrt{\frac{0.318(1-0.318)}{5120}}=0.301

0.318 + 2.58\sqrt{\frac{0.318(1-0.318)}{5120}}=0.335

The 99% confidence interval would be given by (0.301;0.355)

8 0
3 years ago
A class of 40 students has 11 students who ride the bus and 10 students who are in the band. Three of the students who ride the
Alexxandr [17]
The denominator is 40
10-3=7 (number of students in the band who do not ride the bus)
7/40=0.175
0.174*100=17.5% chance
Hope this helps!
8 0
2 years ago
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