Hi Can you check number 5 please If wrong give me right answer

What is the average of 1.90 7.99 4.33 5.21?

nadezda [96]

Add All The Numbers (Which Gives You 19.43) Then Divide By Four Because There Are Four Numbers That Were Added Together. The Average Is 4.8575.

7 0

2 years ago

Read 2 more answers

Solve each equation. Record your work and check your solution. a. 5(x-2)+(-9)= -7(1-x)

Daniel [21]

The solution for equation is x = -6

Solution:

Given equation is:

$5(x-2) + (-9) = -7(1-x)$

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

$5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x$

Solve for terms in left hand side of equation

$5x - 19 = -7+7x$

Move the variables to one side and constants to other side

$7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6$

Thus the solution for equation is x = -6

8 0

2 years ago

Beth drives 200 miles in 4 hours.

Dmitrij [34]

Answer:

26mph

Step-by-step explanation:

18 miles at 36mph will take 30 minutes and 26 × 7 is 3 h 30 min

3 0

2 years ago

Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br

Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0

3 years ago

What is the solution of the system of equations shown in the graph ?

Katarina [22]

The answer is (0,-3) and (0-1)

hope this helped

4 0

2 years ago