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3 years ago

What is 2/5 +1/3= show your work

Mathematics

2 answers:

Scrat [10]3 years ago

6 0

Must find a common denominator

2/5 + 1/3

= 6 + 5/15
= 11/15

natita [175]3 years ago

3 0

The first thing you want to do is get a common denominator. This means the number at the bottom of both fractions is the same.

In this problem it would be fifteen
2/5 x 3/3 = 6/15
1/3 x 5/5 = 5/15

When adding fractions you only add the numerators or the top numbers together. When adding fractions the denominator is NEVER ADDED.
6/15 + 5/15 = 11/15

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If you sell 10 units a week and you have 50 units in inventory, then you have how many weeks of inventory?

Greeley [361]

Answer:

You would have 5 weeks of inventory.

Step-by-step explanation:

50/10=5

3 0

3 years ago

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Kaylee's gross income is $3,200 per month. Of this amount 25% is taken out for taxes and other required deductions. How much is

andrew11 [14]

Answer: $\$2400$

Step-by-step explanation:

Given

Kaylee's gross income is $\$32,000\text{per month}$

$25\%$ is taken out for taxes and other required deduction

left amount is

$\Rightarrow 3200-25\%\times 3200\\\Rightarrow 3200(1-0.25)=\$2400$

So, her take-home pay is $\$2400$

4 0

3 years ago

A national college researcher reported that 65% of students who graduated from high school in 2012 enrolled in college. Twenty n

Usimov [2.4K]

Answer:

a) The probability that exactly 17 of them enroll in college is 0.116.

b) The probability that more than 14 enroll in college is 0.995.

c) The probability that fewer than 11 enroll in college is 0.001.

d) It would be be unusual if more than 24 of them enroll in college since the probability is 0.009.

Step-by-step explanation:

We can model this with a binomial distribution, with n=29 and p=0.65.

The probability that k students from the sample who graduated from high school in 2012 enrolled in college is:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{29}{k} 0.65^{k} 0.35^{29-k}\\\\\\$

a) The probability that exactly 17 of them enroll in college is:

$P(x=17) = \dbinom{29}{17} p^{17}(1-p)^{12}=51895935*0.0007*0=0.116\\\\\\$

b) The probability that more than 14 of them enroll in college is:

$P(X>14)=\sum_{15}^{29} P(X=k_i)=1-\sum_{0}^{14} P(X=k_i)\\\\\\P(x=0)=0\\\\P(x=1)=0\\\\P(x=2)=0\\\\P(x=3)=0\\\\P(x=4)=0\\\\P(x=5)=0\\\\P(x=6)=0\\\\P(x=7)=0\\\\P(x=8)=0\\\\P(x=9)=0\\\\P(x=10)=0.001\\\\P(x=11)=0.002\\\\P(x=12)=0.005\\\\P(x=13)=0.013\\\\P(x=14)=0.027\\\\\\P(X>14)=1-0.005=0.995$

c) Using the probabilities calculated in the point b, we have:

$P(X$

d) The probabilities that more than 24 enroll in college is:

$P(X>24)=\sum_{25}^{29}P(X=k_i)\\\\\\ P(x=25) = \dbinom{29}{25} p^{25}(1-p)^{4}=23751*0*0.015=0.007\\\\\\P(x=26) = \dbinom{29}{26} p^{26}(1-p)^{3}=3654*0*0.043=0.002\\\\\\P(x=27) = \dbinom{29}{27} p^{27}(1-p)^{2}=406*0*0.123=0\\\\\\P(x=28) = \dbinom{29}{28} p^{28}(1-p)^{1}=29*0*0.35=0\\\\\\P(x=29) = \dbinom{29}{29} p^{29}(1-p)^{0}=1*0*1=0\\\\\\\\P(X>24)=0.007+0.002+0+0+0=0.009$

6 0

3 years ago

54 x 44 partial product

Llana [10]

Answer:

2,376

Step-by-step explanation:

--------------

21 6

+ 2160

---------------

2,376

7 0

3 years ago

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H=64t-32t^2 find the maximum height attained by the obiect

pshichka [43]

Check the picture below.

so if we just find its vertex, we know how many feet it went up by its y-coordinate.

$\bf h=64t-32t^2\implies h=-32t^2+64t+0 \\\\[-0.35em] ~\dotfill$

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-32}t^2\stackrel{\stackrel{b}{\downarrow }}{+64}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{64}{2(-32)}~~,~~0-\cfrac{64^2}{4(-32)} \right)\implies \left( \stackrel{\stackrel{\textit{how many}}{\textit{seconds}}}{1}~~,~~\stackrel{\stackrel{\textit{how many feet}}{\textit{it went up}}}{32} \right)$

5 0

3 years ago