Answer:
a) 15.52ft
b) 0.47 secs
Step-by-step explanation:
h = -16t^2 + 15t + 12
The maximum height is reached after -b/2a seconds
a = -16 , b = 15, c= 12
-b/2a = -15/2(-16)
= -15/-32
= 0.47 secs
The maximum height = -16(0.47)^2 + 15(0.47) + 12
= -3.5344 + 7.05 + 12
= 15.5156
= 15.52ft
1. yes
2.no
3.yes
4. no
5. yes
It is a scalene triangle bc it has no equal sides
Answer:
Relative error = 0.0254 %
Step-by-step explanation:
Given details
Height of equipment from base is 104 ft
Elevation angle is 27.5 degree
From figure we have
.........1

x = 54.13 ft
differentiating 1st eq wrt x
![\frac{d}{dx} tan\theta = \frac{d}{dx} [\frac{x}{104}]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20tan%5Ctheta%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bx%7D%7B104%7D%5D)

Taken
for minute change


from 



Reltaive error

Relative error = 0.0254 %