Given: AB = CD 1 = 4 Prove: AD = CB Which of the following triangle congruence theorems would be used in this proof? SSS SAS ASA

Mathematics

1 answer:

vazorg [7]3 years ago

8 0

Answer:

we can use sas theorum

Step-by-step explanation:

since its given 2 sides are congruent its an isoceles trinangle

whhich means angles opposite to equal sides are equal .

You might be interested in

A Galapagos cactus finch population increases by half every decade. The number of finches is

Angelina_Jolie [31]

Answer:

The number of fringes at $d=-2$ is given as 20.

Step-by-step explanation:

Question

A Galapagos cactus finch population increases by half every decade. The number of finches is modeled by the expression

where d is the number of decades after the population was measured. Evaluate the expression for d = −2

Given :

The number of finches is modeled by the expression :

⇒ $45\cdot1.5^d$

where $d$ is the number of decades after the population was measured.

To evaluate the expression for d=-2

Solution:

In order to evaluate the given expression to find the number of finches at $d=-2$ , we will plugin $-2$ for $d$ in the expression and simplify it.

Plugging in $d=-2$ in the expression:

⇒ $45\cdot 1.5^{-2}$

Using negative exponent property. [ $a^{-x}=\frac{1}{a^x}$

⇒ $45\cdot \frac{1}{1.5^2}$

⇒ $45\cdot \frac{1}{2.25}$

⇒ $20$ (Answer)

Thus, the number of fringes at $d=-2$ is given as 20.

This means the number of fringes two decades ago was 20.

6 0

3 years ago

The relationship between the number of gallons of water in a tank and number of hours is proportional. One point on the line mod

Over [174]

Answer:

Step-by-step explanation:

I am assuming the tank starts empty. It means that in 1 hour the tank has half that water, or 3600 gallons. And the good thing of lines passing through 0.0 is that the value at 1 IS the slope we need. ie 3600.

At this point it's easy to find that if in 2 hours it filled 1/10th of the tank, in 20 hours the tank will be full.

Graph done with paint, obviously not to scale.