Hi Joseph2337
x/2 - 5 > - 7
x/2 > -7 + 5
x/2 > -2
x > -2 * 2
Lastly multiply 2 * 2 so it can be 4.
Answer: x > -4
Answer:
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the given information,
x2 = - 1
x1 = 4
y2 = 6
y1 = 3
Therefore,
Distance = √(- 1 - 4)² + (6 - 3)²
Distance = √(- 5² + 3²) = √(25 + 9) = √34
Distance = 5.83
Answer:
1341.2<x<1458.8
Step-by-step explanation:
Given
sample size n = 64
standard deviation = 240
average mean = 1400
z score at 95% CI = 1.96
Required
confidence interval
Confidence interval = xbar ± (z*s/√n)
CI = 1400 ± (1.96*240/√64)
CI = 1400 ± (1.96*240/8)
CI = 1400 ± (1.96*30)
CI = 1400 ± 58.8
CI = (1400-58.8, 1400+58.8)
CI = (1341.2, 1458.8)
Hence the confidence interval for the population is 1341.2<x<1458.8
Did you ever get the answers sis i need them
Answer:
The second method gives the greater heart rate.
Step-by-step explanation:
In the second method, the age and heart rate(bpm) are in a linear relationship.
Therefore, the maximum heart rate for a 90-year-old person in the second method is = 194 - (194 - 187)7 = 145 bpm.
{Since, the maximum heart rate in the second method decreases in an A.P. having value at the age of 20 is 194 and it decreases by 7 bpm per 10 years}
Now, in the first method, the maximum heart rate for 90-year-old person is y = 220 - 90 = 130 bpm.
Therefore, the second method gives a greater heart rate. (Answer)
