Answer:
This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3
Step-by-step explanation:
The given function is

When we differentiate this function with respect to x, we get;

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)
This implies that;




![c-3=\sqrt[3]{63.15789}](https://tex.z-dn.net/?f=c-3%3D%5Csqrt%5B3%5D%7B63.15789%7D)
![c=3+\sqrt[3]{63.15789}](https://tex.z-dn.net/?f=c%3D3%2B%5Csqrt%5B3%5D%7B63.15789%7D)

If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).
But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.
I don’t want nobody to be rude or disrespectful or not texting you or texting you right back but you
Answer:
The answer is
or 1.666...
Step-by-step explanation:
Reorganize the problem
÷
=
Reciprocal the Multiplier
÷
=
x
=
or
or 1 
Hope this helps!
Answer:
Step-by-step explanation:
such a silly question
ask ur teacher
is she gawaar????
Hi,
She lacks 240-42 = 198
She earns 12 usd per hours so : 198 /12 = 16.5