Answer:
Case study.
Explanation:
The research of psychology are mostly based on the observation and experience of the individual. The psychologist must follows the proper rules and regulation of the research.
Dr, Smith research is based especially on the case study. These case study includes the collection of the data from the multiple source. The reaction of the individual is measured on the different visual sensation and different sounds. Quantitative data collection is mostly used in the case study of the Dr. Smith.
Thus, the answer is case study.
Answer:
The neuron will not fire an action potential.
Explanation:
The missing magnitudes of the synaptic potentials when they reach the postsynaptic cell's axon hillock are:
A. excitatory +7
B. excitatory +10
C. inhibitory -3
D. excitatory +2
E. inhibitory -4
To fire the action potential, the summation of excitatory postsynaptic potentials (EPSP) and inhibitory postsynaptic potentials (IPSP) must reach the action potential threshold, which in this case is 15mV more positive than the resting potential.
The EPSP are: +7 +10 +2= +19
The IPSP are: -3 - 4= -7
EPSP + IPSP=
+19 -7 = +12 mV
The neuron will not fire an action potential since the integration of EPSP and IPSP is below 15mv.
Answer:heredity
Explanation:something that’s passed on to some members
<span>A student researching a new discovery about the activity of mitochondria could find the most current and reliable information in a Scientific Journal. This kind of materials provides the latest trends and updates on scientific researches in biological-related fields. They can be found almost always online and a person can subscribe to such materials in case editing is done by the publisher or the author.</span>
Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
</span>
Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2
Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
= proportion of heterozygous population
Answer: percentage of heterozygous population is 48.32%
