Answer: The length of JF = 16 units.
Step-by-step explanation:
Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.
i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]
If EJ is 3y-8 and JF is 7y-40.
Then, 
![\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%207y-3y%3D40-8%5C%5C%5C%5C%5CRightarrow%5C%204y%3D32%5C%5C%5C%5C%5CRightarrow%5C%20y%3D8%20%5Ctext%7B%20%5BDivide%20both%20sides%20by%204%5D%7D)
JF= 7(8)-40 =56-40= 16 units
Hence, the length of JF = 16 units.
Answer:
No
Step-by-step explanation:
Because in a function for every one x there is one y.
<h3>
Answer:</h3>
- One solution: (x, y) = (2, 0)
- Infinitely many solutions: 2x -5y = 17
<h3>
Step-by-step explanation:</h3>
1. When you put the second equation in standard form, it is ...
... 5x +3y = 10
This is a different equation than the first one, so there will be one solution where the lines interect. (Adding the two equations gives 10x=20 ⇒ x=2. Since adding or subtracting y gives the same result, y must be zero.)
2. When you put the second equation in standard form, it is the same as the first:
... 2x -5y = 17 . . . . . divide the equation by 3
That is, any (x, y) values that satisfy the first equation will also satisfy the second equation (since they are the same). There are an infinite number of (x, y) values that do so.
More info please. i need what im finding
Answer:
3/4
Step-by-step explanation:
Hope this helps! :)
