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labwork [276]
4 years ago
5

How do i solve this equation: 15-g=23-2g

Mathematics
2 answers:
victus00 [196]4 years ago
8 0
So first add the g to the -2g so now it is 15=23-g. Then subtract the 23 to the 15. -8=-g so now just divide the negative and the final answer is 8=g
motikmotik4 years ago
4 0
You would move the variables to one side and numbers to the other, so move -2g to the other side to make it positive. That leaves you with g+15=23. Now move 15 to the other side which means it will be negative so subtract 15 from 23 which gives you 8. g = 8
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Please answer fast!!!!!!
ArbitrLikvidat [17]

Answer:

8 and 10

Step-by-step explanation:

Given

\frac{1}{x} + \frac{1}{x+2} = \frac{9}{40} ← combine the fractions on the left side

\frac{x+2+x}{x(x+2)} = \frac{9}{40}

\frac{2x+2}{x^2+2x} = \frac{9}{40} ( cross- multiply )

9(x² + 2x) = 40(2x + 2) ← distribute both sides

9x² + 18x = 80x + 80 ( subtract 80x + 80 from both sides )

9x² - 62x - 80 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 9 × - 80 = - 720 and sum = - 62

The factors are - 72 and + 10

Use these factors to split the x- term

9x² - 72x + 10x - 80 = 0 ( factor the first/second and third/fourth terms )

9x(x - 8) + 10(x - 8) = 0 ← factor out (x - 8) from each term

(x - 8)(9x + 10) = 0

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The integers are 8 and 10

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