Answer:
Step-by-step explanation:
The logistic differential equation is as follows:
In this problem, we have that:
, which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.
At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.
This means that 
when 
. With this, we can find r, that is, the growth rate,
So
So the differential equation is:
<h3>
Answer: 7.4 hours</h3>
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Explanation:
Add up the percentage values:
25+20+6+6+6 = 63
This means 63% of the trip was driven by anyone but Dan. That must mean 100-63 = 37% of the trip is how much Dan drove.
Apply this percentage to the 20 hour duration
37% of 20 = 0.37*20 = 7.4 hours represents how long Dan drove.
extra notes:
- 7.4 hours = 7 hours, 24 minutes because 0.4 hours = 0.4*60 = 24 minutes
- 7.4 hours = 7 hrs + 24 min = 7*60+24 = 444 minutes
Answer:
The two numbers are:
8 and 13
Step-by-step explanation:
a = 2b - 3 Eq. 1
a + b = 21 Eq. 2
Replacing Eq. 1 in Eq. 2:
(2b-3) + b = 21
3b - 3 = 21
3b = 21 + 3
3b = 24
b = 24/3
b = 8
from Eq. 1
a = 2*8 - 3
a = 16 - 3
a = 13
Check:
From Eq. 2:
a + b = 21
13 + 8 = 21
Answer:
Step-by-step explanation:
Let x be the random variable representing the number of miles that each person walked each day for 6 months. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
For Rueben,
µ = 5
σ = 1.1
the probability that Rueben walked more than 6.1 miles is expressed as
P(x > 6.1) = 1 - P( x ≤ 6.1)
For x = 6.1,
z = (4 - 6.1)/1.1 = - 1.91
Looking at the normal distribution table, the probability corresponding to the z score is 0.02807
P(x > 6.1) = 1 - 0.02807 = 0.97193
P(x > 6.1) = 0.97 × 100 = 97%
For Victor,
µ = 4.4
σ = 1.4
the probability that Victor walked less than 5.8 miless is expressed as
P(x < 5.8)
For x = 5.8,
z = (5.8 - 4.4)/1.4 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x < 5.8) = 0.84 = 84%
