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Julli [10]
3 years ago
10

If ZPQR measures 75 what is the measure of ZSQR?

Mathematics
1 answer:
slava [35]3 years ago
6 0

Answer:

Since there's no given exact measurement. I'll assume that the angle is by default 180 degrees.

If angle PQR measure 75 degrees.

then the measurement of angle SQR will be:

Angle PQR = 75

Angle SQR = 180 - 75 degrees

Angle SQR = 105 degree

Step-by-step explanation:

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the sum of two numbers is 70. the larger number is five less than twice the smaller number . what are the two numbers
earnstyle [38]
X+y=70
x=2y-5
x=larger number
y=smaller number
now plug in the value of x to only have one variable in the equation...
Way to solve for y:
(2y-5)+y=70
3y-5=70
add 5 on both sides...
3y=75
divide by 3 on both sides
y=25
1st way to solve for x:
now plug in y in the original equation...
x+25=70
subtract 25 on both sides...
x=45
2nd way to solve for x:
plug in y for the second equation...
x=25(2)-5
x=50-5
x=45
answer: the two numbers are 45 and 25.

3 0
3 years ago
4(5x + 9)^2 – 33 = -21
ozzi

Answer:

x = sqrt(3)/5 - 9/5 or x = -9/5 - sqrt(3)/5

Step-by-step explanation by completing the square:

Solve for x over the real numbers:

4 (5 x + 9)^2 - 33 = -21

Add 33 to both sides:

4 (5 x + 9)^2 = 12

Divide both sides by 4:

(5 x + 9)^2 = 3

Take the square root of both sides:

5 x + 9 = sqrt(3) or 5 x + 9 = -sqrt(3)

Subtract 9 from both sides:

5 x = sqrt(3) - 9 or 5 x + 9 = -sqrt(3)

Divide both sides by 5:

x = sqrt(3)/5 - 9/5 or 5 x + 9 = -sqrt(3)

Subtract 9 from both sides:

x = sqrt(3)/5 - 9/5 or 5 x = -9 - sqrt(3)

Divide both sides by 5:

Answer:  x = sqrt(3)/5 - 9/5 or x = -9/5 - sqrt(3)/5

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HELP ASPAP!!!!! WILL MARK BRAINIEST standard deviation
Umnica [9.8K]

Answer:

The standard deviation of the given data is 11.34.

Step-by-step explanation:

We have to find the standard deviation for the given data;

Grade on     No. of students          

 test (X)        with that score (f)        X \times f       ( X - \bar X)^{2}        f \times ( X - \bar X)^{2}

     50                  1                       50      1073.218      1073.2176

     57                 2                       114      663.578      1327.1552

     60                 4                       240       518.018     2072.0704

     65                 3                       195       315.418      946.2528

     72                 3                       216        115.778       347.3328

     75                12                       900        60.218       722.6112

     77                10                       770        33.178       331.776

     81                 6                       486        3.098       18.5856

     83                 6                       498        0.058        0.3456

     88                9                       792        27.458      247.1184

     90                12                      1080        52.418      629.0112

     92                12                       1104        85.378     1024.5312

     95                 2                        190        149.818      299.6352

     99                 4                        396        263.738     1054.9504

    100          <u>       5   </u>                 <u>    500    </u>     297.218   <u>   1486.088     </u>

   Total             <u>      91       </u>                <u>    7531     </u>                       <u>    11580.68    </u>

Firstly, the mean of the above data is given by;

            Mean, \bar X  =  \frac{\sum X \times f}{\sum f}

                             =  \frac{7531}{91}  =  82.76

Now, the standard deviation of the data is given by;

          Standard deviation, S.D.  =  \sqrt{\frac{\sum f(X-\bar X)^{2} }{\sum f-1}}

                                                     =  \sqrt{\frac{11580.68}{91-1}}

                                                     =  11.34

Hence, the standard deviation of the given data is 11.34.

5 0
3 years ago
What are the domain,range,and asymptote of h(x)=2 to the power of x+2
jeka57 [31]

Domain: (-infinity,infinity)


Range: (0, infinity)


The asymptote is at 0

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