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Mnenie [13.5K]
3 years ago
5

Simplify the expression 4t+10-5-3t in math

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
4 0
(4t+10) - (5-3t) =  
(14t) - (2t) =
Reika [66]3 years ago
3 0
4t + 10 - 5 - 3t: t +5
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3 years ago
Mario walked at a rate of 2/3 miles every 10 minutes what is his unit rate every mile per hour
Dmitry_Shevchenko [17]

Mario's unit rate is given by 900 miles/hour.

Explanation:

We have been given that Mario walked at a rate of 2/3 miles every 10 minutes.

We have the relation between speed, time and distance, which is given by

\text{Speed}= \frac{\text{Distance}}{\text{Time}}

We have,

Distance = \frac{2}{3} \text{ miles}

Time = 10 minutes

On substituting these values in the above formula, we get

\text{Speed} = \frac{2/3}{10}\\\\ \text{Speed} =\frac{2}{10\cdot 3}\\\\ \text{Speed} =[tex]\frac{1}{15} \text{ miles/min}[/tex]

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\frac{1}{15} \times 60\\ = 4 \text{ miles/hour}

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4 years ago
I need help with this iready question​
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3 years ago
A fly that is heterozygous for both traits (GgEe) is crossed with one that has vestigial wings and sepia eyes (see). How many ou
ahrayia [7]

The question is incomplete soI am writing the complete question below:

These letters represent the genotypes and phenotypes of the fruit flies.

GG = Normal Wings           EE = Red Eyes

Gg = Normal Wings           Ee = Red Eyes

gg = vestigial wings           ee = sepia eyes

     

A fly that is heterozygous for both traits (GgEe) is crossed with one that has vestigial  wings and sepia eyes (ggee).

How many out of 16 are normal wings, red eyes?

Answer:

Out of 16 there are <u>4 flies which have normal wings and red eyes.</u>

Step-by-step explanation:

A fly (GgEe) is crossed with (ggee). So we will use a Punnett square to calculate the alleles of their offspring.

For wings i.e. Gg x gg:

         G         g

g       Gg      gg

g       Gg      gg

There are 2 flies with Gg (Normal Wings) and two flies with gg (Vestigial wings. The probability of both is 2/4.

For eyes i.e. Ee x ee

         E        e

e       Ee       ee

e       Ee       ee

There are 2 flies with red eyes (Ee) and 2 flies with sepia eyes (ee). the probability of both is 2/4.

No. of flies with normal wings (Gg) and red eyes (Ee) = 2/4 x 2/4

No. of flies with normal wings (Gg) and red eyes (Ee) = 4/16

So, out of 16 there are <u>4 flies which have normal wings and red eyes</u>.

6 0
4 years ago
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