I think the answer is Light showers
You would use
P^2 = (2π)^2(D^3)/((G)(M))
where P is the orbital period in seconds, D is the distance in meters, M is the mass in kilograms of Jupiter, and G is the 6.67 x 10^ -11 m^3/ kg sec^2
M Jupiter = 1.9 x 10^27 kg, D = 1.88 x10^9 meters
P^2 = 39.5*(6.65 x 10^27)/(( 6.67 x 10^ -11)(1.9 x 10^27)) = 2.07 x 10^12
P = 1,440,000 seconds = 16.66 days
The correct answers are: [C], [E], and [F] .
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Answers:
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[C]: geosphere ;
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[E]: atmosphere ;
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[F]: hydrosphere.
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Answer:
climate, and geography
Explanation:
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