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3 years ago

A scale distance of 3 centimeters on a map represents an actual distance of 51 feet.

2 answers:

8 0

In this case, the best way to work this out is to find what 1cm is equal to. In this case, you have to divide 51/3, giving you 17. You know that 17 feet. You can now divide 187/17, giving you 11. Therefore, 11cm is equal to 187 feet. Hope this helps

Vanyuwa [196]3 years ago

7 0

If the distance is 51 feet in 3 cm
if the destance is 187 feet ..?cm
51 ....3
187...? =3 * 187/51
=3*3.58
=10.74 cm (hope it help)

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C. 7.2°F is warmer than 7.0°F but colder than 7.6°F.

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3 years ago

Victoria saved $150 from babysitting and donated 10% to the local animal shelter how much of the $150 did Victoria donate?

Julli [10]

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2 years ago

What is 6x+3y=-15 in y-intercept form

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Answer:

3y = -6x - 15

Step-by-step explanation:

To put 6x + 3y = -15 into Slope Intercept Form you need to know the formula (y = mx + b) so we know we need to get y on its own side so we can -6x from both side giving us 3y = -6x +-15 or 3y = -6x - 15 There are many different slope intercept forms for this equation depending on how you get y by its self!

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3 years ago

Read 2 more answers

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405

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We can use a ratio to solve

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50 sampled 6750 population

Using cross products

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3 years ago

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Rebecca has 12 photos she wants to hang side by side on her wall.A. If she only wants to display 8 of the photos, in how many wa

Mariana [72]

If she will choose 8 from 12 photos, the total number of ways she can choose is given by a combination of 12 choose 8, since the order of the photos doesn't matter.

The formula for a combination of n choose p is:

$C(n,p)=\frac{n!}{p!(n-p)!}$

For n = 12 and p = 8, we have:

$C(12,8)=\frac{12!}{8!(12-8)!_{}}=\frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4!}=\frac{12\cdot11\cdot10\cdot9}{4\cdot3\cdot2}=495$

So there are 495 ways.

If she wants to arrange the 12 photos, the total number of ways is given by the factorial of 12:

$12!=12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2=479001600$

There are 479,001,600 ways.

Since 10 photos already have specific places, we need to calculate the number of ways to arrange the other two photos in the two remaining places.

In this case, there are only 2 ways of organizing the remaining two photos:

Photo 1 first, photo 2 last, or photo 1 last and photo 2 first.

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1 year ago