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Nataly_w [17]
3 years ago
10

90°

Mathematics
1 answer:
faust18 [17]3 years ago
4 0

Answer: C on ed2020

Step-by-step explanation:

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Is there a x=-2 in these equations
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7 0
3 years ago
The product of two consecutive even integers is 288 find the integers.
algol [13]
Using algebra
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18
this is another solution
as you can see, it's just a matter of factoring 288using arithmetic...√288=16.97≈1716 and 18 are the integers (as well as -16 and -18)
5 0
3 years ago
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