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Alborosie
3 years ago
7

Help me pleased i love you so much

Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0

1) There are 4 tens and 3 ones which equals 43 cents.

2) There is 26 cents in total. There are 2 dimes, and 6 pennies.

3) 3rd choice

4) 1st choice

5) 50, 55, 60, 65

6) 70, 80, 90, 100

7) 50, 60, 70, 80.

Remember:

It is always important to remember the values of each coin in currency. It is also important to do mental math in your head doing addition, subtraction, or maybe even multiplication. Also remember to read closely to each problem.

bezimeni [28]3 years ago
3 0

Answer:

1. Draw 4 in the tens box, and 3 in the ones box. There are 4 tens and 3 ones. The total amount is 43 cents.

2. The total value is 26. There are 2 dimes. Each dime is worth 10 cents. 2 x 10 = 20. There are 6 pennies. Each penny is worth 1 cent. 6 x 1 = 6. 20 + 6 = 26 cents.

3. There are 3 tens and 3 ones.

4. The total value is 33 cents.

5. 50, 55, 60, 65.

6. 70, 80, 90, 100.

7. 50, 60, 70, 80.

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If you're not familiar with that result, it's easy to reproduce.

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\displaystyle S_N = \sum_{n=0}^N \left(6^x - 9\right)^n = 1 + \left(6^x - 9\right) + \left(6^x - 9\right)^2 + \cdots + \left(6^x - 9\right)^N

Multiply both sides by the ratio.

\left(6^x - 9\right) S_N = \left(6^x - 9\right) + \left(6^x - 9\right)^2 + \left(6^x - 9\right)^3 + \cdots + \left(6^x - 9\right)^{N+1}

Subtract this from S_N to eliminate all the powers of the ratio between 0 and N+1.

\left(1 - \left(6^x - 9\right)\right) S_N = 1 - \left(6^x - 9\right)^{N+1}

Solve for S_N.

S_N = \dfrac{1 - \left(6^x - 9\right)^{N+1}}{10-6^x}

Now as N\to\infty, the exponential term converges to 0 and we're left with

\displaystyle \sum_{n=0}^\infty \left(6^x-9\right)^n = \lim_{N\to\infty} S_N = \boxed{\frac1{10-6^x}}

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