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Alborosie
3 years ago
7

Help me pleased i love you so much

Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0

1) There are 4 tens and 3 ones which equals 43 cents.

2) There is 26 cents in total. There are 2 dimes, and 6 pennies.

3) 3rd choice

4) 1st choice

5) 50, 55, 60, 65

6) 70, 80, 90, 100

7) 50, 60, 70, 80.

Remember:

It is always important to remember the values of each coin in currency. It is also important to do mental math in your head doing addition, subtraction, or maybe even multiplication. Also remember to read closely to each problem.

bezimeni [28]3 years ago
3 0

Answer:

1. Draw 4 in the tens box, and 3 in the ones box. There are 4 tens and 3 ones. The total amount is 43 cents.

2. The total value is 26. There are 2 dimes. Each dime is worth 10 cents. 2 x 10 = 20. There are 6 pennies. Each penny is worth 1 cent. 6 x 1 = 6. 20 + 6 = 26 cents.

3. There are 3 tens and 3 ones.

4. The total value is 33 cents.

5. 50, 55, 60, 65.

6. 70, 80, 90, 100.

7. 50, 60, 70, 80.

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following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in
valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs)           Number of households</em>

<em>                  0-30                                                           5</em>

<em>                 30-60                                                          6        </em>

<em>                 60-90                                                          9</em>

<em>                 90-120                                                         6</em>

<em>                 120-150                                                        4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Here, the maximum

l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30

l= is the lower limit of the class

f_{1} = is the frequency of the modal class

f_{0} = is the frequency of the previous modal class

f_{2} = is the frequency of the next previous modal class

l= is the class size

So,

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )

Mode = 60 + \frac{(30)(3)}{6}

Mode = 60 + 15=75

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

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