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DochEvi [55]
4 years ago
13

Find the domain of y=log3(x+5)

Mathematics
1 answer:
Anton [14]4 years ago
7 0
(x+5)>0
D: (-5, infinity)
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What is this? Help me!
VladimirAG [237]

Answer:

4 weeks : 5 books

8 weeks : 10 books

Step-by-step explanation:

alright so she is reading at a rate of 1.25 books per week, we know this becasue we can divide 15/12 which is equal to 1.25. Know we know the rate we can just multiply the rate by the number of weeks, so 4 * 1.25 = 5, and 8 * 1.25 = 10.

7 0
3 years ago
2+y+y+y+y+y+3 I need multiple answers plz and thanks
rodikova [14]

Answer:

5y + 5

5(y + 1)

Step-by-step explanation:

2+y+y+y+y+y+3 = 5y + 5 = 5(y + 1)

8 0
3 years ago
Read 2 more answers
9 stores is 3% of how many stores?
hichkok12 [17]
Hello there! We can solve this question by writing and solving a proportion. Set it up like this:

9/x = 3/100.

This is because 9 is 3% of x number of stores and percents are parts of 100. Setting it up like this will help us get the correct answer. Cross multiply the values . 9 * 100 is 900 and 3 * x = 3x. You get 900 = 3x. Now, divide each side by 3 to isolate the x. 3x/3 cancels out the x. 900/3 is 300. There. x = 300. 9 stores is 3% of 300 stores.
3 0
4 years ago
Read 2 more answers
The explicit formula of an arithmetic sequence is f(n) =3-4(n-1)
Mariulka [41]

Answer:

18th term

Step-by-step explanation:

3-4(n-1) = -65

-4n + 4 = -68

-4n = -72

n = 18

8 0
4 years ago
I need help with 4B please. Thank you!
Basile [38]

The equation to the tangent line to y = e^{(x^2)} at point (1,0) is given by:

y = 2e(x - 1).

<h3>What is the equation to the tangent line of a function of a point?</h3>

Supposing that we have a function f(x) at a point (x_0, y_0), the equation of the tangent line to this function is given by:

y - y_0 = f^{\prime}(x_0, y_0)(x - x_0)

In which f' is the derivative.

In this problem, the function is:

f(x) = e^{(x^2)}

Applying the chain rule, the derivative is:

f^{\prime}(x) = 2xe^{(x^2)}

At x = 1, the derivative is:

f^{\prime}(1) = 2(1)e^{((1)^2)} = 2e

Hence the tangent line at point (1,0) is given by:

y = 2e(x - 1).

More can be learned about the equation of a tangent line at brainly.com/question/8174665

#SPJ1

7 0
2 years ago
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