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3 years ago

I'd appreciate someones help right about now Haha :) I need help :/

Mathematics

2 answers:

My name is Ann [436]3 years ago

3 0

The mean is 6 because you have to add all the numbers and divide by 5

victus00 [196]3 years ago

3 0

The answer is 6.

Explanation:
Since the question is asking for the number of suspensions, we'll only look at the left part of the chart.
The formula for mean is all the numbers added up in the set divided by the amount of numbers.
So, in this problem, we add up 4,5,6,7 and 8 which equals 30, and divide by 5 to get 6.

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HELP WHAT IS -2y+12 + -2y-7

astraxan [27]

Answer
-4y+5

Explanation
You add -2y and -2y which equals -4y, then you add 12 and -7 which equals 5, then just put them in order as they appear in the equation.

4 0

2 years ago

What's the answer to x^2-6x-8?

solong [7]

Answer:

Step-by-step explanation:

(x-4)(x-2)=0

If any individual factor on the left side of the equation is equal to 0

the entire expression will be equal to 0

Set the first factor equal to 0 and solve

x=4

The final solution is all the values that make

(x-4)(x-2)=0

x=4,2

6 0

3 years ago

Divide 320 into 8 equal groups

alexandr402 [8]

Answer:

320 divided by 8 is 40. 40 times 8 is 320, so it works backwards.

8 0

3 years ago

Will give brainiest In △ABC, angle bisectors

EleoNora [17]

Answer:

$m\angle CAB=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=25\dfrac{5}{7}^{\circ}$

Step-by-step explanation:

AK is angle A bisector, then

$m\angle BAK=m\angle KAC=x^{\circ}$

BL is angle B bisector, then

$m\angle ABL=m\angle CBL=y^{\circ}$

Consider triangle ABL. The sum of the measures of all interior angles in this triangle is $180^{\circ},$ then

$m\angle BAL+m\angle ALB+m\angle LBA=180^{\circ}\\ \\2x+2y+y=180\\ \\2x+3y=180$

Consider triangle ABK. In this triangle,

$m\angle AKB=180^{\circ}-2x^{\circ} \ [\text{Supplementary angles}]$

The sum of the measures of all interior angles in this triangle is $180^{\circ},$ then

$m\angle BAK+m\angle AKB+m\angle KBA=180^{\circ}\\ \\x+(180-2x)+2y=180\\ \\2y-x=0$

Hence,

$x=2y\\ \\2(2y)+3y=180\\ \\4y+3y=180\\ \\7y=180\\ \\y=\dfrac{180}{7}=25\dfrac{5}{7}\\ \\x=\dfrac{360}{7}=51\dfrac{3}{7}$

Find the measures of the triangle ABC:

$m\angle CAB=2x^{\circ}=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=2y^{\circ}=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=180^{\circ}-102\dfrac{6}{7}^{\circ}-51\dfrac{3}{7}^{\circ}=25\dfrac{5}{7}^{\circ}$

8 0

4 years ago

Please help me with this radical expression

LenaWriter [7]

Answer:

a. ⁴√x³

d. ¹²√x⁹

Step-by-step explanation:

First, simplify 9⁄12 to ¾. Then, according to the Definition of Rational Exponents [part II], ⁿ√aᵐ = aᵐ\ⁿ, you set your denominator equal to the root, and your numerator becomes your exponent, keeping your base INSIDE the radical.

I am joyous to assist you anytime.

6 0

3 years ago