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3 years ago

How are peptide bonds formed between amino acids in the elongation process of the translation of mRNA?

Biology

1 answer:

ValentinkaMS [17]3 years ago

7 0

Answer:

amino acid meet up inside the ribosome. Once translation has begun, it continues down the line as mRNA shifts along through the ribosome. ... During elongation, amino acids are continually added to the line, forming a long chain bound together by peptide bonds

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What type of bonds within the tertiary structure of an enzyme will break at high temperatures? Which bonds will not break?

Korolek [52]

Answer:

The bonds that will break at high temperature are hydrogen, ionic and Van der Waal's interactions. Covalent bonds will not break.

Explanation:

6 0

3 years ago

Suppose a species of bird called the red-crested warbler has a plumage length that is controlled by a single gene. The Plm allel

AleksAgata [21]

We are going to have different allele frequencies for the two populations

North American:

72 birds total => 144 alleles

72 - 55 birds = 17 short plume birds.

q^2 = (2*17) / 114 = 0.236

Freq(short plume allele) = q = 0.486

Freq(long plume allele) = p = 1 - q = 0.514

From this North American population we get

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds total => 504 alleles

252 - 75 birds = 177 short plume birds.

q^2 = (2*177) / 504 = 0.702

Freq(short plume allele) = q = 0.838

Freq(long plume allele) = p = 1 - q = 0.162

From this South American population we get

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

Blended population has

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (answer)

6 0

3 years ago

Describe how natural selection impacts the evolution of organisms

kherson [118]

Answer:

Natural selection is the process through which populations of living organisms adapt and change. Natural selection can lead to speciation, where one species gives rise to a new and distinctly different species. It is one of the processes that drives evolution and helps to explain the diversity of life on Earth.

Explanation: I hope this is right?

3 0

3 years ago

Question 8 of 11

RideAnS [48]

The answer will be B. Energy produced in the core travels outwards, moving from one particle to the next

8 0

2 years ago

Please help ....... thank you in advance

Anna71 [15]

Answer:

Here's what I get.

Explanation:

Your first problem is to figure out the formula to use.

You have an initial population P₀ that increases each year by 5 %, that is, by a factor of 1.05.

Each year, you multiply the population of the previous year by 1.05.

This gives you a geometric series, for which the general formula is

P = P₀rⁿ

P₀ = 11 500

r = 1.05, the common ratio from one year to the next

n = the number of years from now

The formula for your population is then

P = 11500(1.05)ⁿ

You must create a table with n as the independent variable and P as the dependent value.

I used Excel to create a table showing the population at half-year intervals (see below).

I also created a graph of the population growth.

You are probably aware that this is a completely unrealistic model, because the population cannot exceed the carrying capacity.

Instead, the graph will level off in a logistic growth curve as the population approaches 14 600.

4 0

3 years ago