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lesantik [10]
3 years ago
9

Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1). A. y + 1 = -2(x – 5) B. y – 1

= -2(x – 5) C. y – 5 = -2(x + 1) D. y -5 = -2(x – 1)
Mathematics
1 answer:
Dmitry [639]3 years ago
8 0
The answer is letter a
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The equation 12x² + 4kx + 3 = 0 has real and equal roots, if
sleet_krkn [62]

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<u>I see it! I see it!</u>

Stare at it for a while. First term is 3(2x)^2, third term is 3(1)^2, we are missing a double product, but we can play with k. For the LHS to be 3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3 you just need 4k= \pm12 \rightarrow k=\pm3.

<u>I don't see it...</u>

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