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3 years ago

How would the expression x^3-8 be rewritten using difference of cubes

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

(x - 2)(x² + 2x + 4)

Step-by-step explanation:

A difference of cubes factors in general as

• a³ - b³ = (a - b)(a² + ab + b² )

note 8 = 2³ = 8 ⇒ b = 2 , with a = x

Hence

x³ - 8

= x³ - 2³

= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)

choli [55]3 years ago

3 0

Answer: The rewritten expression would be $(x-2)(x^2+2x+4)$

Step-by-step explanation:

Since we have given that

$x^3-8$

We need to use the difference of cubes:

As we know the formula of "Difference of cubes":

$a^3-b^3=(a-b)(a^2+b^2+ab)$

So, it can be written as

$(x)^3-(2)^3=(x-2)(x^2+2x+4)$

Hence, the rewritten expression would be $(x-2)(x^2+2x+4)$

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3 years ago

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nika2105 [10]

Answer:

For systolic pressure data:

$\bar X =127.2\\\\S=17.91668\\\\CV=\frac{17.91668}{127.2}=0.14085$

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Step-by-step explanation:

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$CV=\frac{\bar X}{S}$

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For systolic pressure data:

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For diastolic pressure data:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

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Best explained and correct answer gets brainliest.

topjm [15]

U = (-2,3)

V = (3,0)

midpoint of UV

= ( (3-2)/2 , (3+0)/2 )

= ( 1/2 , 3/2)

= ( 0.5 , 1.5)

X = (0.5 , 1.5) [from fig]

midpoint of UV = X

W= (-2,-3)

V =( 3.0)

Y = ( (-2+3)/2 , (-3+0)/2 )

= (0.5 , - 1.5)

Y = ( 0.5 , -1.5) [ from fig ]

Y is the midpoint of WV

by midpoint theorem ,

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3 years ago

How would the expression x^3-8 be rewritten using difference of cubes ​

How would the expression x^3-8 be rewritten using difference of cubes