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3 years ago

How would the expression x^3-8 be rewritten using difference of cubes

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

(x - 2)(x² + 2x + 4)

Step-by-step explanation:

A difference of cubes factors in general as

• a³ - b³ = (a - b)(a² + ab + b² )

note 8 = 2³ = 8 ⇒ b = 2 , with a = x

Hence

x³ - 8

= x³ - 2³

= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)

choli [55]3 years ago

3 0

Answer: The rewritten expression would be $(x-2)(x^2+2x+4)$

Step-by-step explanation:

Since we have given that

$x^3-8$

We need to use the difference of cubes:

As we know the formula of "Difference of cubes":

$a^3-b^3=(a-b)(a^2+b^2+ab)$

So, it can be written as

$(x)^3-(2)^3=(x-2)(x^2+2x+4)$

Hence, the rewritten expression would be $(x-2)(x^2+2x+4)$

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Answer:

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Step-by-step explanation:

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b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

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How would the expression x^3-8 be rewritten using difference of cubes ​

How would the expression x^3-8 be rewritten using difference of cubes