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3 years ago

PLS HELP! NO GUESSING 5r + r3s IS IT A MONOMIAL YES OR NO EXPLAIN ANSWER

2 answers:

6 0

Nope, <span>5r + r3s is not a monomial.
Monomials cannot include addition or subtraction, and since this uses addition, it is not a monomial.
</span>

I hope this helps and have a great day! If you need anymore help you can link me to another question and I will try to solve it!

Annette [7]3 years ago

5 0

No, this is not a monomial. An monomial example is 2xy^2, this is a trinomial.

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How many pounds and ounces are in 95 ounces?

S_A_V [24]

There are 95 ounces and 5.9375 pounds.

4 0

3 years ago

Please help asap!!!!

igor_vitrenko [27]

Answer:

$m\widehat {MP} =46\degree$

Step-by-step explanation:

By inscribed angle theorem:

$m\angle MQP=\frac{1}{2} \times \widehat {MP}$

$23\degree =\frac{1}{2} \times m\widehat {MP}$

$23\degree \times 2= m\widehat {MP}$

$m\widehat {MP} =46\degree$

7 0

3 years ago

A polynomlal has been factored, as SHOWI Deluw.

Tom [10]

Answer:

The zeros are 6,-5,9

Step-by-step explanation:

The factored form of the polynomial is given as:

$f(x) = (x - 6)(x + 5)(x - 9)$

To find the zeros of this function, we set f(x)=0 and solve for x.

$(x - 6)(x + 5)(x - 9) = 0$

This implies that:

$(x - 6) = 0 \: or \: (x + 5) = 0 \: or \: (x - 9) = 0$

We solve for x to get:

$x = 6 \: or \: x = - 5 \: or \: x = 9$

The zeros are 6,-5,9

3 0

3 years ago

What is the sum of the first five terms of the geometric sequence in which a1=10 and r=1/2?

Tomtit [17]

(10(1-(1/2)^5)/1-(1/2) =

20(1-1/32)
=155/8

5 0

3 years ago

Read 2 more answers

Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.

vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

$\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}$

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

$\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}$

So, it becomes,

$\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ$

Hence, the value of cos theta is -0.352.

8 0

3 years ago