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mr_godi [17]
3 years ago
10

Find two consecutive odd integers such that their product is 59 more than 2 times their sum

Mathematics
1 answer:
svetlana [45]3 years ago
8 0
Let n and n+2 be the integers. Then:
n(n+2)-59=2(n+n+2)
n²+2n-59-4n-4=0
n²-2n-63=0
(n-9)(n+7)=0
n=9 or -7
n+2=11 or -5


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Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.
Jet001 [13]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

|a|=\left\{\begin{array}{ccc}a&for\ a\geq0\\-a&for\ a

Put each value of x from the set {2, 3, 4, 5, 6}

to the equation y = 2|x - 4| + 3:

x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)

x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)

x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)

x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)

x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)

Mark the points in the coordinates system.

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bearhunter [10]
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For n =0

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For n =1

a_1=4(1)-6=-2

For n =2

a_2=4(2)-6=2

For n =3

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Therefore, the first four terms of the sequence are

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IrinaK [193]

<em>Answer:</em>

24.64

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