the length of a rectangle is five less than twice it's width.if the perimeter of the rectangle is 56 inches,find its dimensions.
2 answers:
P = 2(L + W) P = 56 L = 2W - 5 56 = 2(2W - 5 + W) 56 = 2(3W - 5) 56 = 6W - 10 56 + 10 = 6W 66 = 6W 66/6 = W 11 = W <=== width is 11 inches L = 2W - 5 L = 2(11) - 5 L = 22 - 5 L = 17 <=== length is 17 inches
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