Answer:
The reduced row-echelon form of the linear system is
Step-by-step explanation:
We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:
- Interchange two rows
- Multiply one row by a nonzero number
- Add a multiple of one row to a different row
To find the reduced row-echelon form of this augmented matrix
You need to follow these steps:
- Divide row 1 by 2
- Subtract row 1 from row 2
- Subtract row 1 multiplied by 5 from row 3
- Subtract row 2 multiplied by 3 from row 1
- Subtract row 2 multiplied by 3 from row 3
- Multiply row 2 by 2
- Divide row 3 by −19
- Subtract row 3 multiplied by 16 from row 1
- Add row 3 multiplied by 6 to row 2