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never [62]
3 years ago
7

What is the equation for the line

Mathematics
1 answer:
Darya [45]3 years ago
8 0
That depends the line
1, If the line is not parallel to Oy, so its equation is y=ax+b
2, Or its equation is x=m
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Formula for the area of a circle in terms of its circumference
Usimov [2.4K]
\bf \textit{circumference of a circle}\\\\
C=2\pi r\qquad \qquad \implies \cfrac{C}{2\pi }=\boxed{r}\\\\
-------------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad \qquad \implies A=\pi \left( \boxed{\cfrac{C}{2\pi }} \right)^2\implies A=\pi \left( \cfrac{C^2}{(2\pi )^2} \right)
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A=\cfrac{\pi  C^2}{2^2\pi^2}\implies A=\cfrac{C^2}{4\pi }
5 0
3 years ago
Plz help best answer gets brainly
lorasvet [3.4K]
Round up to 1, 400 then times it by 5

1,400 • 5 = 7,000

So no, it it's not reasonable.
7 0
3 years ago
A diver dove to a location 6 3/5 below sea level.He then drove to a second location 8 1/5 meters below sea level.How many meters
laiz [17]

Answer:

2 2/5

Step-by-step explanation:

3 0
3 years ago
The volume of a sphere is 4/3pi cm^3<br> what is the diameter of the sphere?
aleksandrvk [35]

The Diameter of sphere is 2cm.

Step-by-step explanation:

Given,

Volume of sphere = \frac{4}{3}\pi \ cm^3

Let,

diameter = d

As we know,

Volume of sphere = \frac{4}{3}\pi \ r^3

Therefore,

\frac{4}{3}\pi\ r^3 = \frac{4}{3}\pi \\Multiplying\ both\ sides\ by\ \frac{3}{4\pi }\\\frac{3}{4\pi }*\frac{4}{3}\pi \ r^3 = \frac{4}{3}\pi * \frac{3}{4\pi }\\r^3=1\\(r)^3=(1)^3\\r=1

We know that,

Diameter = 2r

Diameter = 2*1

Diameter = 2 cm

The Diameter of sphere is 2cm.

Keywords: Volume, Diameter

Learn more about diameters at:

  • brainly.com/question/12973601
  • brainly.com/question/13063819

#LearnwithBrainly

3 0
3 years ago
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
3 years ago
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