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elena-14-01-66 [18.8K]
3 years ago
5

The area of a blackboard is 1 1 third square yards. A poster's area is 8 over 9 square yards. What is the unit rate of the black

board's area to the poster's area?
Mathematics
1 answer:
Darya [45]3 years ago
6 0

Step-by-step explanation:

Given that,

The area of a blackboard is 1\dfrac{1}{3}=\dfrac{4}{3}\ \text{yards}^2

The area of poster is \dfrac{8}{9}\ \text{yards}^2

We need to find the unit rate of the blackboard's area to the poster's area. So, it can be calcualted by dividing blackboard's area to the poster's area.

So,

\dfrac{\dfrac{4}{3}}{\dfrac{8}{9}}=\dfrac{4}{3}\times \dfrac{9}{8}\\\\=1.5

So, the rate of 1.5\ \text{yard}^2.

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user100 [1]

Answer:

where is the point?

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Step-by-step explanation:

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4 years ago
Read 2 more answers
tom and lisa each had a birthday party at hurricane harbor last weekend . the cost of admission was $137.50 for 13 children and
gregori [183]

Answer:

Per child admission costs $8.5

Per Adult admission costs $13.5

Step-by-step explanation:

Let x be the amount of admission per child and y be the amount of admission per adult

For Tom's party:

13x+2y=137.50      (Equation 1)

For Lisa's Party:

9x+2y=105.50       (Equation 2)

Using Elimination Method:

Add Equation 1 & 2

13x+2y=137.50

9x+2y=105.50  

-    -   = -         (Change of Signs)

---------------------------------

4x+0y=34.00      

x=34/4

x=8.5

Putting the value of x in Equation 2

13(8.5)+2y=137.50

110.5+2y=137.50

2y=137.50-110.50

2y=27

y=27/2

y=13.5

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3 years ago
Please help :(
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Length A is 4 ft. after a dilation is performed length B is 7ft. what was the scale factor used?
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1.75

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