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3 years ago

Wiil mark bianleast plz plz hlpe

Mathematics

2 answers:

Andrews [41]3 years ago

5 0

Answer:

18 since 12 x 2 = 24 so 9 x 2 = 18

Step-by-step explanation:

morpeh [17]3 years ago

4 0

Answer:

18 ft

Step-by-step explanation:

12 * 2 = 24

9 * 2 = 18

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By selling a radio with 12% profit , the profit

Setler79 [48]

Answer:

the Radio was 52.8%

Step-by-step explanation:

60-12%=52.8

5 0

2 years ago

If a,b and c are numbers such that a:b:c = 2:3:5 and b= 30 then, find the sum of a+b+c ?

ladessa [460]

Answer:

100

Step-by-step explanation:

2:3:5

20:30:50

20 + 30 + 50 = 50 + 50 = 100

3 0

3 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check al

Alla [95]

Let's rewrite each equation in the Slope-Intercept Form of the Equation of a Line. First, let's start with the main equation:

$\bullet \ 5x-2y=-6 \therefore y=\frac{5}{2}x+3$

Then, our options are the following:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \therefore y=-\frac{2}{5}x-2 \\ \\ C) \ 2x-5y=-10 \therefore y=\frac{2}{5}x+2 \\ \\ D) \ y+4=-\frac{2}{5}(x-5) \therefore y=-\frac{2}{5}x-2 \\ \\ E) \ y-4=\frac{5}{2}(x + 5) \therefore y=\frac{5}{2}x+\frac{33}{2}$

For two perpendicular lines it is true that the product of its slopes is:

$m_{1}m_{2}=-1$

$m_{1}m_{2}=-1 \\ \\ m_{1} \ is \ the \ slope \ of \ y=\frac{5}{2}x+3, \ that \ is, \ m_{1}=\frac{5}{2} \\ \\ Then, \ the \ slope \ of \ a \ perpendicular \ line \ is: \\ \\ m_{2}=-\frac{2}{5}$

According to this, only A) B) and D) might be the perpendicular lines we are looking for. Notice that these lines are the same. The other condition is that the line must pass through the point (5, -4). By substituting this point in the equation, we have:

$y = -\frac{2}{5}x-2 \\ \\ -4=-\frac{2}{5}(5)-2 \\ \\ -4=-2-2 \\ \\ \boxed{-4=-4} \ True!$

Finally, the right answer are:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \\ \\ D) \ y+4=-\frac{2}{5}(x-5)$

8 0

2 years ago

Read 2 more answers

Prove that equation ax^2+2hxy+by^2 always represent a pair of straight lines passing through the origin

GarryVolchara [31]

You should try a calculator 2 6

4 0

2 years ago

Express x and y in terms of trigonometric ratios of 0.

Georgia [21]

SIN(θ) = OPPOSITE / HYPOTENUSE = X / Y
COS(θ) = ADJACENT / HYPOTENUSE = 2 / Y
TAN(θ) = OPPOSITE / ADJACENT = X / 2
CSC(θ) = 1 / SIN(θ) = 1 / (X / Y) = Y / X
SEC(θ) = 1 / COS (θ) = 1 / (2 / Y) = Y / 2
COT (θ) = 1 / TAN(θ) = 1 / (X / 2) = 2 / X
HUNEY, YOU HAVE ALL OF THE VALUES, NOW JUST SOLVE FOR X AND Y THEN...
FOR EXAMPLE:
SIN(θ) = X / Y X = Y * SIN(θ)
COS(θ) = 2 / Y Y = 2 / COS(θ)
TAN(θ) = X / 2 X = 2 * TAN(θ)
SO ON, SO FORTH HUN U GET IT

4 0

2 years ago